What is the prime factorization of 128?

The prime factorization of 128 can be found by dividing the number by its smallest prime factor, which is 2, and then continuing to divide the resulting factors by their smallest prime factors until all factors are prime numbers.

In the case of 128: 128 ÷ 2 = 64 64 ÷ 2 = 32 32 ÷ 2 = 16 16 ÷ 2 = 8 8 ÷ 2 = 4 4 ÷ 2 = 2 2 ÷ 2 = 1

Therefore, the prime factorization of 128 is: 2 x 2 x 2 x 2 x 2 x 2 x 2 = 2^7.